The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak isA. `100muA`B. `0.01mA`C. `0.25mA`D. `500muA`

The transfer ration of a transistor is `50`. The input resistance of t

1.	The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak isA. `100muA`B. `0.01mA`C. `0.25mA`D. `500muA`
Answer» Correct Answer - D `beta=50,R_(i)=1000 Omega,v_(i)=0.01V` `v_(i)=DeltaI_(B)R_(i)impliesDeltaI_(B)=(0.01)/(1000)=10^(-5)A` `beta=(DeltaI_(C ))/(DeltaI_(B))impliesDeltaI_(C )=betaDeltaI_(B)=50xx10^(-5)A=500muA`

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The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak isA. `100muA`B. `0.01mA`C. `0.25mA`D. `500muA`

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