The trigonometric equation `sin^(-1)x=2sin^(-1)a`has a solution forall

1.	The trigonometric equation `sin^(-1)x=2sin^(-1)a`has a solution forall real values (b) `\|a\|
Answer» Correct Answer - C `sin^(-1) x = 2 sin^(-1) a` Now `-(pi)/(2) le sin^(-1) a le(pi)/(2)` `rArr -(pi)/(4) le sin^(-1) a le (pi)/(4)` `rArr -(1)/(sqrt2) le a le (1)/(sqrt2)` `rArr \|a\| le (1)/(sqrt2)`

Discussion

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