InterviewSolution
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InterviewSolution
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The two ends of a train moving with constantacceleration pass a certain point with velocities uand 3u. The velocity with which the middle point ofthe train passes the same point is(1) 2u(2) u2(3) y5 u(4) 10 u |
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Answer» S = (v^2 - u^2) / (2a) If Length of train is L thenL = ((3u)^2 - u^2) / (2a)L = 4u^2 / a —-(1) Midpoint is at Distance L/2S = (v^2 - u^2) / (2a)L/2 = (v^2 - u^2) / (2a)From equation (1)2u^2 / a = (v^2 - u^2) / (2a)4u^2 = v^2 - u^2v^2 = 5u^2v = u√5 option(c) ty |
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