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The vale of `sec(sin^-1(sin((-50pi)/9))+cos^-1(cos(31pi)/9))`A. `sec.(10pi)/(9)`B. `sec.(pi)/(9)`C. 1D. `-1` |
Answer» Correct Answer - D `sin^(-1)(-sin.(50pi)/(9))=sin^(-1)(sin(-6pi+(4pi)/(9)))` `=sin^(-1)(sin.(4pi)/(9))` `=(4pi)/(9)` `cos^(-1)cos(-(31pi)/(9))=cos^(-1)cos((31pi)/(9))` `=cos^(-1)cos(4pi-(5pi)/(9))=cos^(-1)cos.(5pi)/(9)=(5pi)/(9)` Hence, given equals to sec `((4pi)/(9)+(5pi)/(9))=sec pi =-1`. |
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