1.

The value for `DeltaU` for the reversible isothermal evaporation of 90 g water at `100^(@)C` will be `(DeltaH_("evap")" of water "=40.8" kJ mol"^(-1), R=8.314"J K"^(-1)"mol"^(-1))`A. 4800 kJB. `188.494 kJ`C. `40.8 kJ`D. `125.03 kJ`

Answer» Correct Answer - B
`DeltaH" for 18 g water = 40.8 kJ"`
`"For 90 g water "=(40.8)/(18)xx90=204kJ`
`"n for 90 g water "=90//18=5`
`Deltan_(g)=5-0=5`
`DeltaH=DeltaU+Deltan_(g)RT`
`DeltaU204000-(5xx8.314xx373)=188494 or 188.494 kJ`


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