1.

The value of 1/(1 – cot2 α) + 1/(1 – tan2 α) is equal to1). -1/22). -13). 14). ½

Answer»

cotα = cosα/sinα, tanα = sinα/cosα

1/(1 – cot2 α) + 1/(1 – tan2 α) = [sin2 α/(sin2 α – cos2 α)] + [cos2 α/( cos2 α - sin2 α)] =

[sin2 α/(sin2 α – cos2 α)] - [cos2 α/(sin2 α – cos2 α)] = 1


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