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The value of a machine depreciates at the rate of 20% per annum. It was purchased 2 years ago. If its present value is Rs. 40000 for how much was it purchased? A. Rs. 56000 B. Rs. 62500 C. Rs. 65200 D. Rs. 56500 |
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Answer» Let value of a machine 2 years ago, = P Present value of machine = Rs.40000 Time, n = 2 years Rate of depreciates, R = 20% per annum Now, Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest P = Present value R = Annual interest rate n = Time in years] ∴ Value = P (1 - R/100)n [∵ Rate decreases] ⇒ 40000 = P (1 - 20/100)2 ⇒ 40000 = P (1 - 1/5)2 ⇒ 40000 = P (4/5)2 ⇒ 40000 = P × 16/25 ⇒ P = 40000 × 25/16 ⇒ P = 2500 × 25 ⇒ P = 62500 ∴ Value of a machine 2 years ago is Rs.62500. |
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