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The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs. 43740, find its purchase price |
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Answer» Given, Depreciation rate of machine = 10% p.a Present value of machine = Rs.43740 Let its purchase price 3 years ago = Rs. x So, \(=x({1}+\frac{10}{100})({1}+\frac{10}{100})({1}+\frac{10}{100})\) = 43740 \(x\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}\) = 43740 \(= x =\frac{43740 \times 10 \times 10 \times 10}{11 \times 11 \times 11}\) = 60000 Hence, Purchase price of machine was = Rs.60000 |
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