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The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs 8748, its purchase price was (a) Rs 10000 (b) Rs 11372 (c) Rs 12000 (d) Rs 12500 |
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Answer» (c) Rs 12000 Let the purchase price of the machine be Rs x. Then, 8748 = x\(\big(1-\frac{10}{100}\big)^3\) = x x \(\frac{9}{10}\) x \(\frac{9}{10}\) x \(\frac{9}{10}\) \(\Rightarrow\)x = \(\frac{8748\times1000}{729}\) = Rs 12000. |
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