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The value of amplitude at an antinode , on an undamped one dimensional stationary wave of wavelength 1.2 m, is 5mm. Then the value of amplitude of particle at a distance of 10cm from an node isA. 5mmB. 7.07mmC. 2.5mmD. 1mm |
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Answer» Correct Answer - C `R=2Asin (2pix)/(lamda)` `=5xx10^(-3)xxsin(2pixx10^(-1))/(1.2)` `=5xx10^(-3)sin pi/6=5xx10^(-3)xx1/2` =2.5mm |
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