InterviewSolution
Saved Bookmarks
| 1. |
The value of cos(-480°) is: (a) √3 (b) \(-\frac{\sqrt{3}}{2}\)(c) \(\frac{1}{2}\)(d) \(\frac{-1}{2}\) |
|
Answer» (d) \(\frac{-1}{2}\) cos(-480°) = cos 480° [∵ cos(-θ) = cos θ] = cos(360° + 120°) = cos 120° = cos(180° – 60°) = -cos 60° = \(\frac{-1}{2}\) |
|