The value of `cot(cose c^(-1)5/3+tan^(-1)2/3)`is:(1) `6/(17)`(2) `3/(17)`(2) `4/(17)`(4) `5/(17)`

The value of `cot(cose c^(-1)5/3+tan^(-1)2/3)`is:(1) `6/(17)`(2) `3/(1

1.	The value of `cot(cose c^(-1)5/3+tan^(-1)2/3)`is:(1) `6/(17)`(2) `3/(17)`(2) `4/(17)`(4) `5/(17)`
Answer» `cosec^-1 5/3 = theta_1` `cosec theta_1 = 5/3` `tan^-1 (2/3) = theta_2` `tan theta_2 = 2/3` now, `cot(tan^-1(3/4) + tan^-1 (2/3) )` `= cot(tan^-1((3/4 + 2/3)/(1 - 3/4 * 2/3)))` `= cot(tan^-1((17/2)/(1/2)))` `= cot(tan^-1(17/6))` `= cot theta_3` `= 6/17` option 1 is correct

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