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The value of cot`[sin^(-1){cos(tan^(-1)1)}]` is |
Answer» We know that `tan^(-1)1=(pi)/(4)` `therefore cot[sin^(-1){cos(tan^(-1)1)}]` `=cot{sin^(-1)(cos(pi)/(4))}=cot(sin^(-1))(1)/sqrt(2)=cot(pi)/(4)=1` |
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