1.

The value of \(\frac{1}{cosec(-45°)}\) is:(a) \(\frac{-1}{\sqrt{2}}\)(b) \(\frac{1}{\sqrt{2}}\)(c) √2 (d) -√2

Answer»

(a) \(\frac{-1}{\sqrt{2}}\)

\(\frac{1}{cosec(-45°)}\) = sin(-45°)

= -sin 45° 

\(\frac{-1}{\sqrt{2}}\)



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