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The value of \(\frac{2tan30°}{1+tan^230°}\) is: (a) \(\frac{1}{2}\)(b) \(\frac{1}{\sqrt{3}}\)(c) \(\frac{\sqrt3}{2}\)(d) √3 |
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Answer» (d) √3 We know that sin 2A = \(\frac{2tanA}{1+tan^2A}\) \(\frac{2tan30°}{1+tan^230°}\) = sin(2 x 30°) = sin 60° = \(\frac{\sqrt{3}}{2}\) = tan 2A = tan 60° = √3 |
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