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The value of `int_(0)^(pi//2)` log (sinx) dx isA. `(pi)/(2) ` log 2B. `pi` log 2C. `-(pi)/(2)` log 2D. `2pi` log 2 |
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Answer» Correct Answer - A Let `I = int _(0)^(pi//2) log (cosec x) dx` `= int_(0)^(pi//2) log ((1)/(sinx)) dx` ` = - int_(0)^(pi//2) log sin x `dx `= (pi)/(2) ""log 2` `[because int_(0)^(pi//2) log sin x dx = - (pi)/(2)""log 2`] |
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