1.

The value of \(\left( {{{\sin }^2}16\frac{{1^\circ }}{2} + {{\sin }^2}73\frac{{1^\circ }}{2}} \right)\) is1). 12). 23). 04). 4

Answer»

$(\Rightarrow \;\LEFT( {{{\SIN }^2}16\FRAC{{1^\circ }}{2} + {{\sin }^2}73\frac{{1^\circ }}{2}} \right)\; = \;\left( {{{\sin }^2}16\frac{{1^\circ }}{2} + {{\sin }^2}(90 - 16\;\frac{{1^\circ }}{2}} \right)\; = \;\left( {{{\sin }^2}16\frac{{1^\circ }}{2} + {{\cos }^2}16\frac{{1^\circ }}{2}} \right))$

(? sin2x + cos2x = 1)

= 1



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