InterviewSolution
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InterviewSolution
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The value of `log_(10)` K for a reaction `A hArr B` is ( Given `: Delta _(r) H_(298K)^(@)= -54.07kJ mol^(-1),Delta_(r)S_(298K)^(@) = 10J K^(-1)mol^(-1)` and`R = 8.314 JK^(-1) mol^(-1), 2.303 xx 8.314 xx 298 K = 5705) `A. 5B. 10C. 95D. 100 |
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Answer» Correct Answer - b `DeltaG^(@) =DeltaH^(@) - T Delta S^(@)= - 2.303 RT log _(10) K` `:. -2.303 RT log_(10) K= DeltaH ^(@)- T DeltaS^(@)` i.e., `-2.303 xx 8.314 xx 298 xx log_(10)K` `=- 54.07xx 1000 - 298 xx 10` `-5705 log_(10)K =- 54070 - 2980 = - 57050` or `log_(10)K =10` |
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