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The value of log `(k_(2))/(k_(1))` is equal toA. `(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`B. `(E_(a))/(2.303R)[(T_(1)T_(2))/(T_(2)-T_(1))]`C. `(E_(a))/(2.303R)[(T_(2)+T_(1))/(T_(1)T_(2))]`D. `(E_(a))/(2.303R)[(T_(1)T_(2))/(T_(1)+T_(2))]` |
Answer» Correct Answer - A The value of `log.(k_(2))/(k_(1))` is equal to `(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]` |
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