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The value of rate constant for a first order reaction `2.303 xx 10^(-2) sec^(-1)` .what will be time required to reduce the concentration to `(1)/(10)` th its initial concentrationA. 10 secondB. 100 secondC. 2303 secondD. 230.3 second |
Answer» Correct Answer - b `t = (2.303)/(K)` log `([A_(0)])/([A])` `t = (2.303)/(2.303 xx 10^(-2)) "log" (100)/(10) implies t = 10^(2)` log 10 `implies t = 100` sec |
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