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The value of sec233° + sin227° – cot257° + sin263° is1). 02). 13). 24). \(\frac{1}{2}\) |
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Answer» sec233° + sin227° – cot257° + sin263° = sec233° – cot2(90° – 33°) + sin227° + sin2(90° – 27°) (? cot (90 – X) = tan x & sin (90 – x) = cos x) = sec233° – tan233° + sin227° + cos227° (? sin2x + cos2x = 1 &sec2x – tan2x = 1) = 1 + 1 = 2 ∴ sec233° + sin227° – cot257° + sin263° = 2 |
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