1.

The value of sec233° + sin227° – cot257° + sin263° is1). 02). 13). 24). \(\frac{1}{2}\)

Answer»

sec233° + sin227° – cot257° + sin263°

= sec233° – cot2(90° – 33°) + sin227° + sin2(90° – 27°)

(? cot (90 – X) = tan x & sin (90 – x) = cos x)

= sec233° – tan233° + sin227° + cos227°

(? sin2x + cos2x = 1 &sec2x – tan2x = 1)

= 1 + 1 = 2

∴ sec233° + sin227° – cot257° + sin263° = 2


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