1.

The value of `Sigma_(n=1)^(3) tan^(-1)(1)/(n)` is

Answer» We have
`underset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=tan^(-1)+tan^(-1)1/2+tan^(-1)1/3`
`rarr underset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=(pi)/(4)O+tan^(-1)((1/2+1/3)/(1-1/2xx1/3))`
`rarrunderset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=(pi)/(4)+tan^(-1)1=(pi)/(4)+(pi)/(4)=(pi)/(2)`


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