

InterviewSolution
Saved Bookmarks
1. |
The value of `Sigma_(n=1)^(3) tan^(-1)(1)/(n)` is |
Answer» We have `underset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=tan^(-1)+tan^(-1)1/2+tan^(-1)1/3` `rarr underset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=(pi)/(4)O+tan^(-1)((1/2+1/3)/(1-1/2xx1/3))` `rarrunderset(n=1)overset(3)Sigma tan^(-1)(1)/(n)=(pi)/(4)+tan^(-1)1=(pi)/(4)+(pi)/(4)=(pi)/(2)` |
|