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The value of `sin^(-1)[cos{sin^(-1)(-sqrt(3)/(2))}]` isA. `(pi)/(3)`B. `(pi)/(6)`C. `-(pi)/(3)`D. `-(pi)/(6)`

Answer» `sin^(-1)[cos{sin^(-1)(-sqrt(3)/(2))}]`
`=sin^(-1){cos(-(pi)/(3))}` [before `sin^(-1)sqrt(3)/(2)=-(pi)//(3)`
`=sin^(-1)(cos(pi)/(3))=sin^(-1)(1/2)=(pi)/(6)`


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