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The value of `sin^(-1)`(sin 10) isA. `3pi-10`B. `10-3pi`C. `3pi+10`D. `4pi-10` |
Answer» We know that `sin^(-1)(sin theta)=theta if -(pi)/(2)letheta le(pi)/(2)` Here `theta =10` radians which does not lie between `-(pi)/(2) and (pi)/(2)` But `3pi-theta` lies between `-(pi)/(2)and (pi)/(2)` also `sin(3pi-10)=sin10` `therefore sin^(-1)(sin10)=sin^(-1)sin(3pi-10)=3pi-10` |
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