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The value of sin 28° cos 17° + cos 28° sin 17° (a) \(\frac{1}{\sqrt{2}}\)(b) 1 (c) \(\frac{-1}{\sqrt{2}}\)(d) 0 |
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Answer» (a) \(\frac{1}{\sqrt{2}}\) sin 28° cos 17° + cos 28° sin 17° = sin(28° + 17°) This is of the form sin(A + B), A = 28°, B = 17° = sin 45° = \(\frac{1}{\sqrt{2}}\) |
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