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The value of sin(-420°) (a) \(\frac{\sqrt{3}}{2}\)(b) \(-\frac{\sqrt{3}}{2}\)(c) \(\frac{1}{2}\)(d) \(-\frac{1}{2}\) |
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Answer» (b) \(-\frac{\sqrt{3}}{2}\) sin(-420°) = -sin(420°) [∵ sin(-θ) = -sin θ] = -sin(360° + 60°) = -sin 60° = \(-\frac{\sqrt{3}}{2}\) |
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