1.

The value of sin(-420°) (a) \(\frac{\sqrt{3}}{2}\)(b) \(-\frac{\sqrt{3}}{2}\)(c) \(\frac{1}{2}\)(d) \(-\frac{1}{2}\)

Answer»

(b) \(-\frac{\sqrt{3}}{2}\)

sin(-420°) = -sin(420°) [∵ sin(-θ) = -sin θ] 

= -sin(360° + 60°) 

= -sin 60° 

\(-\frac{\sqrt{3}}{2}\)



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