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The value of tan 1°.tan 2° tan 3° equal to(A) -1 (B) 1(C) π/2(D) 2 |
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Answer» Correct option is (B) 1 tan1° tan2° tan3° … tan89° = (tan 1° tan 89°) (tan 2° tan 88°) …(tan 44° tan 46°) tan 45° = (tan 1 ° cot 1 °) (tan 2° cot 2°) …(tan 44° cot 44°) . tan 45° …tan(∵ 90° – θ) = cot θ] = 1 x 1 x 1 x … x 1 x tan 45° = 1 |
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