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The values of a and b for which the two circles :x2+ y2+ 2(1 –a)x + 2(1 + b)y + (2 –c) = 0 and x2+ y2+ 2(1 + a)x + 2(1 –b)y + (2 + c) = 0 cut orthogonally are? |
Answer» 2[g1g2 +f1f2] =c1 +c2 a=0 and b=0 |
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