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The velocity of a body of mass 10kg increases from 4m/s to 8m/s when a force acts on it for 2sec. (a)what is the momentum before the force act?(b)what is the momentum after the force act ?(c) what is the gain in momentum per second?(d)what is the value of the force?​

Answer» TION:Mass of the body =10 kgInitial velocity u=4 m/sFinal velocity v=8 m/sTime t=2sa) MOMENTUM before force acts P 1 =m×u=10×4=40kg.m/sb) Momentum after force acts p 2 =m×v=10×8=80kg.m/sc) Gain in momentum per second = 240 =20kg.m/sd) Acceleration a= tv−u = 28−4 =2m/s 2 Force =m×a=10×2=20 N


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