InterviewSolution
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InterviewSolution
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The velocity of a particle moving in the positivedration d xais vaiesByscx./x , where α ispositive constant. Assuming that at the moment t0, the particle was located at x 0 the value of timedependence of the velocity and the acceleration ofthe particle -(A) 2022t 2(C) α2 , α2(D) of these |
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Answer» Given v = a √x x = 0 when t = 0 v = dx / dt = a √x=> dx/√x = a dt integrate on both sides=> 2 √x = a t + c x = 0 at t = 0 => c = 0 => x = a²t²/4 (differentiate now: wrt t)=> v = a² t /2 (differentiate now wrt t) => acceleration = a² / 2 hence, option (b) is correct |
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