1.

The velocity of an electron in theBohn's first onbit of a hydrogen atomis 2:19X100m/s. Its velocity in the secondorbit would bei​

Answer»

Answer:

We KNOW that angular momentum REMAINS conserved so MV

1

r

1

=mv

2

r

2

so v

2

=

r

2

r

1

v

1

We know that according to Bohr postulate r

n

=n

2

a

0

, where a

0

is radius of ground orbit=r

1

So v

2

=

2

2

a

0

1

2

a

0

v

1

=

4

v

1

=

4

2.19

×10

6

m/s=5.5×10

5

m/s

Explanation:

We know that angular momentum remains conserved so mv

1

r

1

=mv

2

r

2

so v

2

=

r

2

r

1

v

1

We know that according to Bohr postulate r

n

=n

2

a

0

, where a

0

is radius of ground orbit=r

1

So v

2

=

2

2

a

0

1

2

a

0

v

1

=

4

v

1

=

4

2.19

×10

6

m/s=5.5×10

5

m/s


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