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the velocity of an object increases at a constant rate from 30m/s to 70m/s comes to stop in 7s. Find the acceleration.​

Answer» <html><body><p>ocity of an object increases at a constant rate from 30m/s to 70m/s <a href="https://interviewquestions.tuteehub.com/tag/comes-2017383" style="font-weight:bold;" target="_blank" title="Click to know more about COMES">COMES</a> to stop in 7s. Find the acceleration.<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> = 70m/s ; v = 0 [ because as we know that if an object comes to rest than v = 0 ] ; t = 7secWe have to use the first equation of motion.➣ v = u + at➣ 0 = 70 + <a href="https://interviewquestions.tuteehub.com/tag/7t-1921579" style="font-weight:bold;" target="_blank" title="Click to know more about 7T">7T</a>➣ 7t = -70➣ t = -70/7➣ t = -10 m/s² ( Or )We can you the acceleration <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> also to find.➣ a = ( 0 - 70 )/7➣ a = -70/7➣ a = -10 m/s²</p></body></html>


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