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the velocity of an object increases at a constant rate from 30m/s to 70m/s comes to stop in 7s. Find the acceleration.​

Answer»

ocity of an object increases at a constant rate from 30m/s to 70m/s COMES to stop in 7s. Find the acceleration.U = 70m/s ; v = 0 [ because as we know that if an object comes to rest than v = 0 ] ; t = 7secWe have to use the first equation of motion.➣ v = u + at➣ 0 = 70 + 7T➣ 7t = -70➣ t = -70/7➣ t = -10 m/s² ( Or )We can you the acceleration FORMULA also to find.➣ a = ( 0 - 70 )/7➣ a = -70/7➣ a = -10 m/s²



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