the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displ

1.	the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displacement of particle from t=1 to t=2 is?
Answer» Answer: We know that velocity is dt dx =v=4t so dx=4tdt integrating both SIDES we get ∫ x 1 x 2 dx=∫ t=2 t=4 4tdt or displacement =x 2 −x 1 =2T 2 ∣ 2 4 =2(16−4)=24m

the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displacement of particle from t=1 to t=2 is?

Answer»

Answer:

We know that velocity is

=v=4t so dx=4tdt

integrating both SIDES we get ∫

dx=∫

t=2

t=4

4tdt

or displacement =x

−x

=2T

∣

=2(16−4)=24m

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the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displacement of particle from t=1 to t=2 is?​

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the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displacement of particle from t=1 to t=2 is?