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The velocity-time relation of an electron starting from rest is given by u=id, where `k=2m//s^(2)`. The distance traversed in 3 sec is:-A. 9mB. 16mC. 27mD. 36m |
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Answer» Correct Answer - A `u=ktrArr (ds)/(dt)=kt (because k= 2m//s^(2))` `rArr int_(0)^(x)ds=2int_(0)^(3)tdt` `rArr s=2|(t^(2))/(2)|_(0)^(2)rArr s=9m` |
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