1.

The vertices of a triangle ABC are A (1,-2, 2), B (1, 4, 0) and C (-4, 1, 1) respectively. If M be the foot of perpendicular drawn from B on AC, then `vec BM` is

Answer» `tantheta=|(m_1-m_2)/(1+m_1m_2)|`
`tantheta=|((-3/4)+1)/(1+3/4)|`
`tantheta=1/7`
`tantheta=|(m+3/4)/(1-3/4m)|`
`1/7=|(4m+3)/(4-3m)|`
`1/7=(4m+3)/(4-3m)`
`m=-17/31,-1`
`3x+4y=5`
`x+y=1`
`3(1-y)+4y=5`
`3-3y+4y=5`
`3+y=5`
`y=2,x=-1`
`y-2=-17/31(x+1)`
`31y+17x-45=0`
`31y+17x=45`
option b is correct.


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