The voltage across a lamp is V = (6.0 + - 0.1) volt and the current pa

1.	The voltage across a lamp is V = (6.0 + - 0.1) volt and the current passing through it I = (4+ - 0.2) ampere. Find the power consumed by the electric lamp. Given Power = V*I
Answer» Answer: The power consumed by the lamp is, \bold{P=(24 \PM 1.6) W}P=(24±1.6)W Here is the solution: The voltage across a lamp is V = (6.0+_ 0.1) v The CURRENT passing through it is (4+-0.2) A By using formula, Power = VI P = 64 = 24 Watt dP = P(dV/V + dI/I) dP = 24(0.1/6 + 0.2/4) dP = 1.6 Therefore, answer:- Power consumed = (24 ± 1.6) Watt Explanation:* I hope it is helpful to you and mark me as brainliest

The voltage across a lamp is V = (6.0 + - 0.1) volt and the current passing through it I = (4+ - 0.2) ampere. Find the power consumed by the electric lamp. Given Power = V*I

Answer»

Answer:

The power consumed by the lamp is, \bold{P=(24 \PM 1.6) W}P=(24±1.6)W

Here is the solution:

The voltage across a lamp is V = (6.0+_ 0.1) v

The CURRENT passing through it is (4+-0.2) A

By using formula, Power = V*I

P = 6*4 = 24 Watt

dP = P(dV/V + dI/I)

dP = 24*(0.1/6 + 0.2/4)

dP = 1.6

Therefore, answer:- Power consumed = (24 ± 1.6) Watt

Explanation:

I hope it is helpful to you and mark me as brainliest

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