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                                    The volume of a gas is reduced adibatically to `(1//4)` of its volume at `27^(@)C` if `y = 1.4` The new temperature will beA. `300 xx (4)^(0.4) K`B. `150 xx (4)^(0.4) K`C. `250 xx (4)^(0.4) K`D. None of these | 
                            
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Answer» Correct Answer - a For adiabatic change the relation between temperature and volume is `TV^(gamma-1) = "constant"` where `gamma` is ratio of specific heats of the gas Given `T _(1) = 27 + 273 = 300 K , V_(1)= V, V_(2) = (V)/(4)` `T_(1)V_(1)^(gamma- 1) = T_(2) V_(2)^(gamma - 1)` `rArr T_(2) = ((V_(1))/(V_(2)))^( gamma - 1) xx T_(1)` `T_(2)= ((V)/(V//4))^(1.4 - 1) xx 300` `T_(2) = (4)^(0.4) xx 300 xx (4)^(0.4) K`.  | 
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