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A gun fires a bullet of mass `50 g` with a velociy of `30 m//s`. Due to this, the gun is pushed back with a velocity of `1 m//s`, then the mass of the gun is :A. `1.5 kg`B. `5.5 kg`C. `0.5 kg`D. `3.5 kg` |
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Answer» Correct Answer - A Momentum remains conserved in the process. If no external force acts upon a system of two(or more) bodies then the toatal momentum of the system remains constant. Hence, momentum before collision= momentum after collision `m_(1)u_(1)=m_(2)v_(2)` Given, `u_(1)=1 m//s,m_(2)=0.05 kg,v_(2)=0.05 kg,v_(2)= 30m//s` `implies m_(1)xx1= 0.05xx30` `implies m_(1)= 1.5 kg` |
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