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Dimension of resistance in an elecatrical circuit, in terms of dimension of mass `M`, of length `L`, of time `T`, and of current `I`, would beA. `[ML^(2)T^(3)I^(-I)]`B. `[ML^(2)T^(2)]`C. `[ML^(2)L^(-1)]`D. `[ML^(2)T^(3)]` |
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Answer» Correct Answer - D Resistance `R=("potential di fference")/("Current")=V/i=W/(qi)` (`:.` Potential difference is equal to work done per unit charge) So, Dimension of `R` `=(["Dimension of work"])/(["Dimension of charge"]["Dimension of current"])` `=([ML^(2)T^(-2)])/([IT][I])=[ML^(2)T^(-3)I^(-2)]` |
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