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A spherical drop of water has `1mm` radius. If the surface tension of water is `70xx10^(-3)`N//m, then the difference of pressure between inside and outside of the spherical drop is:A. `140 N//m^(2)`B. `14 N//m^(2)`C. `35 N//M^(2)`D. None of the above |
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Answer» Correct Answer - A Let the radius of drop be `R` and surface tension water be `T`. Then the excess pressure of difference pressure between inside and outside of the spherical drop is given by `P=(2T)/(R )` Given, `R=1 mmm= 1xx10^(-3)m` `T= 70xx10^(-3)N//m` `:. P=(2xx70xx10^(-3))/(1xx10^(-3))= 140 N//m` |
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