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The volume of a tetrahedronformed by the coterminous edges ` vec a , vec b ,a n d vec c`is 3. Then the volume of the parallelepipedformed by the coterminous edges ` vec a+ vec b , vec b+ vec ca n d vec c+ vec a`is`6`b. `18`c. `36`d. 9 |
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Answer» Volume of tetrahedron= `1/6*[veca vecb vecc]=3` Hence, `[vec(a) vec(b) vec(c)]=18` Volume of parallelopiped=` [vec(a+b) vec(b+c) vec(c+a)]` = `2[veca vecb vecc]` =2*18=36. |
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