The volume of cone of diameter’d’ and height ‘h’ is ………

1.	The volume of cone of diameter’d’ and height ‘h’ is ……… units3.A) πd2/2B) πd2h/12C) πdh2/12D) πd2/12
Answer» Correct option is: B) \(\frac{\pi d^2 h}{12}\) Diameter of the cone is d. \(\therefore\) Radius of the cone is r = \(\frac d2\) Height of the cone is h. \(\therefore\) Volume of cone = \(\frac 13 \pi r^2h\) = \(\frac 13 \pi \) (\(\frac d2\))\(^2\) h = \(\frac {\pi \, d^2h}{12}\) cubic units. Correct option is: B) \(\frac{\pi\,d^2h}{12}\)

The volume of cone of diameter’d’ and height ‘h’ is ……… units3.A) πd2/2B) πd2h/12C) πdh2/12D) πd2/12

Answer»

Correct option is: B) \(\frac{\pi d^2 h}{12}\)

Diameter of the cone is d.

\(\therefore\) Radius of the cone is r = \(\frac d2\)

Height of the cone is h.

\(\therefore\) Volume of cone = \(\frac 13 \pi r^2h\) = \(\frac 13 \pi \) (\(\frac d2\))\(^2\) h = \(\frac {\pi \, d^2h}{12}\) cubic units.

Correct option is: B) \(\frac{\pi\,d^2h}{12}\)