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The wavelength for n=3 to n=2 transition of the hydrogen atom is 656.3 nm. What are the wavelength for this same transition in (a) positronium, which consists of an electron and a positron (b) singly ionized helium |
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Answer» Correct Answer - A::B::C::D (a) Reduced mass of positronium and electron is `(m)/(2),` where, m = mass of electron `E prop m :. lambda prop (1)/(m)` m has become half, so `lambda` will become two times or 1312 nm or `1.31 mum.` . For singly ionixed helium atom Z =2 `:. lambda is (1)/(4) th or 164 nm` |
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