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The work done in moving 6 μC charge between two points is 1.2 × 10-5J. Find the potential difference between two points |
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Answer» ∆v=2 Explanation: W=q(∆v) ∆v=w/q ∆v=1.2×10^-5 ÷ 6×10^-6 =12÷6 =2
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