The work done to get `n` smaller equal size spherical drops from a bigger size spherical drop of wate is proportional to :A. `(1/(n^(2//3)))-1`B. `(1/(n^(1//3)))-1`C. `n^(1//3)-1`D. `n^(4//3)-1`

The work done to get `n` smaller equal size spherical drops from a big

1.	The work done to get `n` smaller equal size spherical drops from a bigger size spherical drop of wate is proportional to :A. `(1/(n^(2//3)))-1`B. `(1/(n^(1//3)))-1`C. `n^(1//3)-1`D. `n^(4//3)-1`
Answer» Correct Answer - C

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The work done to get `n` smaller equal size spherical drops from a bigger size spherical drop of wate is proportional to :A. `(1/(n^(2//3)))-1`B. `(1/(n^(1//3)))-1`C. `n^(1//3)-1`D. `n^(4//3)-1`

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