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Theangle between A and B is θ. The value of the tri-ple product A. BxA is(a) AB(CASB sin θ(b) zero(d) A2B cos θ. |
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Answer» since B×A will be a vector that will be _|_ to both A and B now for product of _|_ vector with A will always be 0 , because angle will be 90° and cos(90°) =0 |
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