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There are two equipotential surafce as shown in figure. The distance between them is `r`. The charged of `-q` coulomb is taken from the surface A to B, the resultant work done will be A. `W = (1)/(4pi epsilon_(0)) (q)/(r )`B. `W = (1)/(4pi epsilon_(0)) (q)/(r^(2))`C. `W = -(1)/(4pi epsilon_(0)) (q)/(r^(2))`D. `W =` zero |
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Answer» Correct Answer - D The work done is given by `= q (V_(2) - V_(1)) = 0` |
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