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There is 1 mol liquid (molar volume 100 ml) in an adiabatic container initial, pressure being 1 bar. Now the pressure is steeply increased to 100 bar ,and the volume decreased by 1 mL under constant pressure of 100 bar. Calculate `DeltaH "and" DeltaE`. [Given 1 bar = `10^(5) N//m^(2)`]A. `DeltaE=0 J, DeltaHne0 J`B. `DeltaH=990 J, DeltaE=10 J`C. `DeltaE=20 J, DeltaH=890 J`D. `DeltaE=0 J, DeltaH=10 J`

Answer» Correct Answer - B


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