1.

There Is A 5 Digit No. Sum Of 3 Pairs Of Digits Is Eleven Each. Last Digit Is 3 Times The First One. 3rd Digit Is 3 Less Than The Second. 4th Digit Is 4 More Than The Second One. Find The Number?

Answer»

We are GIVEN a 5 digit number

Let FIRST digit be 'X'

then 5th digit is '3X'

let 2ND digit be 'Y'

then 3rd digit is 'Y - 3'

and 4th digit is 'Y + 4'

then the no is '(X)(Y)(Y - 3)(Y + 4)(3X)'

from the above we can say 3X <= 9

so X<=3 and any of the digit in the number is <= 9

and also given that 3 pairs sum is 11... 

Also Y–3 ≥ 0 and Y+4 ≤ 9

⇒ Y ≥ 3 and Y ≤ 5 i.e. Y = 3,4 or 5

for x = 1, all the conditions won’t be satisfied.

For x = 2,

Let Y = 5

∴ The number is 25296

We are given a 5 digit number

Let first digit be 'X'

then 5th digit is '3X'

let 2nd digit be 'Y'

then 3rd digit is 'Y - 3'

and 4th digit is 'Y + 4'

then the no is '(X)(Y)(Y - 3)(Y + 4)(3X)'

from the above we can say 3X <= 9

so X<=3 and any of the digit in the number is <= 9

and also given that 3 pairs sum is 11... 

Also Y–3 ≥ 0 and Y+4 ≤ 9

⇒ Y ≥ 3 and Y ≤ 5 i.e. Y = 3,4 or 5

for x = 1, all the conditions won’t be satisfied.

For x = 2,

Let Y = 5

∴ The number is 25296


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