1.

Every Day A Cyclist Meets A Train At A Particular Crossing. The Road Is Straight Before The Crossing And Both Are Traveling In The Same Direction. The Cyclist Travels With A Speed Of 10 Kmph. One Day The Cyclist Comes Early By 25 Min. And Meets The Train 5km Before The Crossing. What Is The Speed Of The Train?

Answer»

Cyclist SPEED is 10kmph and he'll take 30 MIN to cover 5 KMS

If Cyclist come 25 min early he would be 5 min before crossing. 

So it means train takes 5 min to reach crossing. 

We have speed of train calculated as 

⇒ Speed= distance/time 

⇒ Speed = 5km/5 min 

⇒ Speed = 1 km/min 

Or 60 km/hr

Cyclist speed is 10kmph and he'll take 30 min to cover 5 kms. 

If Cyclist come 25 min early he would be 5 min before crossing. 

So it means train takes 5 min to reach crossing. 

We have speed of train calculated as 

⇒ Speed= distance/time 

⇒ Speed = 5km/5 min 

⇒ Speed = 1 km/min 

Or 60 km/hr



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