InterviewSolution
Saved Bookmarks
| 1. |
Every Day A Cyclist Meets A Train At A Particular Crossing. The Road Is Straight Before The Crossing And Both Are Traveling In The Same Direction. The Cyclist Travels With A Speed Of 10 Kmph. One Day The Cyclist Comes Early By 25 Min. And Meets The Train 5km Before The Crossing. What Is The Speed Of The Train? |
|
Answer» Cyclist SPEED is 10kmph and he'll take 30 MIN to cover 5 KMS. If Cyclist come 25 min early he would be 5 min before crossing. So it means train takes 5 min to reach crossing. We have speed of train calculated as ⇒ Speed= distance/time ⇒ Speed = 5km/5 min ⇒ Speed = 1 km/min Or 60 km/hr Cyclist speed is 10kmph and he'll take 30 min to cover 5 kms. If Cyclist come 25 min early he would be 5 min before crossing. So it means train takes 5 min to reach crossing. We have speed of train calculated as ⇒ Speed= distance/time ⇒ Speed = 5km/5 min ⇒ Speed = 1 km/min Or 60 km/hr |
|